How to solve the problem of button response? (anxious!!!)

dreamcity · Post time: 2020-1-20 01:00:01

Two datagrids are made in one page, as a voting option, and the next voting button, I want to make the button Enabled = false after clicking the voting button, but the button needs to be refreshed after the page properties (because there are more voting items, So it takes a certain amount of time to update the data, so it is only possible to change it in order to prevent repeated submissions. Is there any other way to directly change its properties after clicking. Thanks for the solution!

3521565 · Post time: 2020-1-28 16:00:02

js implementation

<% @ Page Language = "C #" AutoEventWireup = "true" CodeFile = "aaa.aspx.cs" Inherits = "aaa"%>

<! DOCTYPE html PUBLIC "-// W3C // DTD XHTML 1.0 Transitional // EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns = "http://www.w3.org/1999/xhtml">
<head runat = "server">
    <title> Untitled page </ title>
</ head>
<body>
    <form id = "form1" runat = "server">
    <div>
      <asp: TextBox ID = "TextBox1" runat = "server"> </ asp: TextBox>
      <asp: Button ID = "Button1" runat = "server" OnClick = "Button1_Click" Text = "Button" OnClientClick = "this.form.submit (); this.disabled = true" UseSubmitBehavior = "False" /> </ div>
    </ form>
</ body>
</ html>

using System;
using System.Data;
using System.Configuration;
using System.Collections;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;

public partial class aaa: System.Web.UI.Page
{
  protected void Page_Load (object sender, EventArgs e)
  {
    if (Page.IsPostBack)
    {
      Button1.Attributes.Add ("disabled", "disabled");
    }

  }
  protected void Button1_Click (object sender, EventArgs e)
  {
    string a = TextBox1.Text;
    Response.Write (a);
  }
}

dreamcity · Post time: 2020-1-29 22:54:01

Tried it, but it became unavailable directly after clicking submit without updating the data.

3521565 · Post time: 2020-1-30 09:45:01

UseSubmitBehavior = "False"
Delete try

zhouji700 · Post time: 2020-1-30 10:45:01

<body>
    <form id = "form1" runat = "server">
    <div>
      <asp: TextBox ID = "TextBox1" runat = "server"> </ asp: TextBox>
      <asp: Button ID = "Button1" runat = "server" Text = "Button" OnClientClick = "document.form1.btn2.click (); this.disabled = true" />
<asp: Button ID = "btn2" runat = "server" OnClick = "Button1_Click" Text = "Button" />
</ div>
    </ form>

Page_Load () writes:
btn2.Attributes.Add ("style", "display: none");

winnest20 · Post time: 2020-1-30 11:18:02

There is only one solution
With an html button, a server-side button, set the server-side button to be invisible
When pressing the html button, write a JS, html button name. Enable = false, and perform the click process of the server-side button

After performing the postback, write a js code html button name on the server side. Enable = true

The specific code of the web form is as follows:
js code
function Send (val)
  {
  document.all.BtnSend.click ();
  document.all.BtnSending.disabled = true;

  }
form
<form id = "FormRoleSet" method = "post" runat = "server">
<!-Here is the html button->
<input style = "WIDTH: 141px; HEIGHT: 20px" id = "BtnSending" name = "BtnSending" onclick = "Send ()"
type = "button" value = "Send mail">
<!-Here is the server-side button->
<asp: button id = "BtnSend" style = "DISPLAY: none" runat = "server" Width = "133px" Text = "Send Email"> </ asp: button>
</ form>

After processing on the server side, go to your page itself or use js to display the button.

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