Ask about the Shannon limit

激流堡见证者

Suppose the telephone line bandwidth is 3kHz, the signal-to-noise ratio is 30dB, and the signal power is 100mW. Find: the maximum data transmission speed (b / s); noise power (mW).

How do I do the above question?
Please let me know ...


Thank you

urzaiz

Maximum data transmission speed = 3k * log2 (1 + 1000)
30db = 10db * log (S / N) == >> Noise power = 100mw / 1000;

激流堡见证者

What does 30db = 10db * log (S / N) mean?

Why is 30db equal to the latter?

sunnylld

This is a formula created by the bird named Shannon, but the maximum transmission speed depends on another theorem called Nyquist. It’s acid to see which is bigger, but Nyquist is theoretical, and there is no signal-to-noise ratio involved.