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How to take a function as a formal parameter into another function for execution?

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Post time: 2020-10-15 09:30:02
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Like the title, please tell me more in detail. Thank you
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Post time: 2020-10-15 10:45:01
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Speak with code

#include <stdio.h>
#include <stdlib.h>

void fun1( int i, double d ){
  printf("fun1: i=%d d=%f\n",i,d);
}


void fun2( int i, double d ){
  printf("fun2: i=%d d=%f\n",i,d);
}

void F(int x, double y, void (*func)( int, double ))
{
        func(x,y);

}

int main()
{
  F(1,2,&fun1);
  F(1,2,&fun2);
  exit(0);

}
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Post time: 2020-10-15 11:15:01
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Just pass a function pointer type to the formal parameters of the function.
The one upstairs is correct. . . .
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Post time: 2020-10-15 11:45:01
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With function pointer
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Post time: 2020-10-15 12:00:01
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Function pointer
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Post time: 2020-10-15 12:15:01
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1231456
correct
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Post time: 2020-10-15 12:30:01
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It is recommended to use typedef to define function pointers
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