A simple C language problem

逍遥无敌

for (int i=0;i<=10;i++)
int s=0;
In the second cycle, is the original space released in the first time?

corpseiori

Can you debug this thing? Look at the execution process and you will know it. Compilation environments such as VC or Dev-cpp have this function.

哈哈大侠

for (int i=0;i<=10;i++)
int s=0;
-------------
More standardized writing
int i = 0;
int s = 0;

for(i = 0;i <= 10;i++)
{
   s = 0
}
i and s are local variables that apply for address space in the stack. The for loop is just a value-added operation and no space is released.

逍遥无敌

The one on the second floor doesn't seem to understand what I mean!

hellolgz

Is S a local variable???
I think so?!

woshibaliu

This is a non-standard way of writing. The C language does not support applying for space at any time. It is estimated that the compilation will not pass.

ycsigimusal

Or add static

redhat2020

Try it in Dev-cpp

今天真高兴

Will be released. The lifetime of a local variable starts at the declaration and ends at the end of its scope. Change the program to
for(int i=0;i<=10;i++)
{
if(i==0) int s=1;
    else s++;
}
Just see it.

edwinlee

#include <cstdio>
int main()
{
for (int i = 0; i <10; i++)
{
int s = 0;
s++;
printf("%d", s);
}
}
The result is 111111, indicating that it has been released