Numerical conversion

candy_26

A 16-bit binary number consisting of two bytes, with the most significant bit being the sign bit.
pVal [1] high byte pVal [0] low byte How do I convert this 16-bit binary number?
 
short CMainFrame :: Get2RealVal (BYTE * pVal)
{
short Val = 0;

if (pVal [1]&0x80 == 0)
{
Val = pVal [1] * 256 + pVal [0];
}
else
{
Val = pVal [1] * 256 + pVal [0];
Val = Val ^ 0xffff + 1;
}
Ranch
return Val;
}

Is there anything wrong with this?

hamnhamn3

Isn't forced conversion possible?

short Val = *(short*)pVal

ps. Provided that the current system is little endian

zdl_22

short val = 0;
val = pVal[0] + pVal[1] * 256;

Or the one upstairs is OK and fast