Why is the output value incorrect from the predetermined value? Please come in.

shuqiang98

long a = 116;
long b = 20;
long c = 43;
long d = (a + (double) b / 60 + (double) c / 3600) * 100000;
cout << "d =" << d << endl;

Why is the output d = 11634527?
Rounding by calculator should be 11634528.

Can anyone tell me what the problem is? How to solve it?

菜鸟级高手

Not rounded when processed by a computer
It converts decimals to integers.

shuqiang98

Is there any way to get the correct value?

rainfruit

Use rounding functions, or do it yourself

stoneboy4000

Add 0.5 before rounding

yashiroxyz

Is there any way to get the correct value?
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What is the correct value? Is the rounded result the correct value? Analyze specific issues!