How to release the secondary pointer? Ask everyone for help!

we4004

unsigned char ** pMyArray = new unsigned char * [nMyArrayNum];
Used when releasing
delete [] pMyArray;
The result will be an error.
With loop, delete pMyArray [i]
It doesn't work either.
I ask heroes to help!

Question supplement: Use the following code, there is no problem when compiling and linking, but an error will pop up when running.
if (pMyArray! = NULL)
{
delete [] pMyArray;
pMyArray = NULL;
}
The pointer memory in the array is still useful, so it is not deleted, only the pointer array is deleted.

yangkern

Where do you apply for space?

chengwei2537

delete [] pMyArray [i]

pretendersam

> How to release the secondary pointer?
-------------------------
Delete pMyArray [i] first, then delete pMyArray

> The pointer memory in the array is still useful, so it will not be deleted, only the pointer array.
-------------------------
Then don't delete it, wait until you don't need to delete it again, or don't use the second pole pointer.

we4004

yangkern: Where do you apply for space?

At the time of definition, we applied for space for the array of pointers, and then used the elements of this array as pointers. The address pointed to by the elements has already been applied. Here, we only use pointers to assign values.

xietao405

Level by level
Agree withpretendersam
> int ** p = new int * [N];
> for (i = 0; i <N; i ++)
> p [i] = new int [N];
>
> for (i = 0; i <N; i ++)
> delete [] p [i];
> delete [] p;

sevenbox

Agree upstairs

we4004

Got it, my question, the array is out of bounds. . . Ugh. . .
thank you all! ! !

we4004

I'm so sorry. . . What a shame. . .