Read the file below, why is the running result 1 2 3 4 5 6 7 7 an additional 7

fordzyb

#include <fstream.h>
void main ()
{
ofstream fout ("d:\\intdata.dat");

int a [7] = {1,2,3,4,5,6,7};
for (int i = 0; i <7; i ++)
fout.write ((char *)&a [i], 4);
fout.close ();


ifstream fin ("d:\\intdata.dat");

int x;
 do {
fin.read ((char *)&x, 4);
cout << x << "";
} while (! fin.eof ());
fin.close ();

}

不大会玩

do {
fin.read ((char *)&x, 4);
cout << x << "";
} while (! fin.eof ());

You judge after reading first, if you write while in front, it won't be much

fordzyb

After the correction, the correct result cannot be obtained. . . . .

wydsln

fin.read ((char *)&x, 4); // read one first, then

while (! fin.eof ()) {
cout << x << "";
fin.read ((char *)&x, 4);
}

orangedj

while (fin.read ((char *)&x, 4)&&! fin.eof ()) {
cout << x << "";
}

orangedj

After reading seven, it will not cause the eof () test to be "true". When reading the eighth, eof () is true, so there is an additional 7

orangedj

Or change it
while (! fin.eof ()&&fin.read ((char *)&x, 4)) {
cout << x << "";
}

lgy_666

You open the file and take a look. If it is correct, your file ends with a space. I also encountered this problem. Press backspace and remove the space. That means the file should not be a space at the end, it should be 7. . The mouse cursor is next to 7

zfy010317

int a [7] = {1,2,3,4,5,6,7};
for (int i = 0; i <7; i ++)
fout.write ((char *)&a [i], 4);

Write files 1,2,3,4,5,6,7
Then it is normal to read 1,2,3,4,5,6,7 when reading.

fordzyb

Please expert guidance. . . . . Still not working, why would I read it again