How to represent 0 of short type?

cqgang

The landlord knows packing, don't you know unpacking?

393736105

When it is running, I don't know what type of box to disassemble.

393736105

Because this value may be one of int, short, or long, I have no other way except to compare them one by one.

cqgang

short a = 0;
object obj = a;
short aa = (short)obj;
bool b = (aa==0);
System.Console.WriteLine(b);

393736105

Dude despise me too much, if it's that simple, I won't ask:

short aa = (short)obj;
How do I know to use shot to cast instead of long...

cqgang

//Now there is no other way except to compare one by one
correct

if (obj is short)
{
    short aa = (short)obj;
}
if (obj is int)
{
    int aa = (int)obj;
}

393736105

It seems that it can only be written like this. I looked at the integer table which has the following types:
sbyte byte char short ushort int uint long ulong
To know the zero value they correspond to, you can only write it in the following way:

if (object.Equals(obj, (sbyte)0) || object.Equals(obj, (byte)0) || object.Equals(obj, (char)0) || object.Equals(obj, (short) 0) || object.Equals(obj, (ushort)0) || object.Equals(obj, (int)0) || object.Equals(obj, (uint)0) || object.Equals(obj, ( long)0) || object.Equals(obj, (ulong)0))
{
     System.Console.WriteLine("zero value");
}
else
{
    System.Console.WriteLine("Non-zero value");
}

芬恩克莱尔

//Now there is no other way except to compare one by one
correct


Isn't it enough to just use Convert? Convert.ToDouble or Convert.ToInt64


In addition, short j = i + 2; the reason for this compilation error is thatcqgangsaid that the short type cannot participate in the operation, that is, short + short will become int.

    short i, j;
    i = j = 1;
   
    short k = i + j;

This program cannot be compiled either...

芬恩克莱尔

If you are sure that ulong will not appear, just use Convert.ToInt64...

393736105

It’s also a way to use one type of mandatory representation, but it may be "distorted" if you turn around.
This is why I did not adopt this method.