Does standard C have a reference type

p23rhkar2k

I have a function void f (int & a) {
 a + = 1;

}
I want to increase the value of a by 1 in f, and does not need to refer to * a as the parameter, can I use the method? Compilation failed. what else can we do?

luowenqi1

There is a problem with the definition of this function. The address character cannot be used as a formal parameter.&is an operator, not a variable type. There are two methods:
1) Use pointers as parameters
void f (int * a) {
 (* a) + = 1;
}
2) Rely on the return value
int f (int a) {
 a + = 1;
return a;
}

squallxuk

Obviously not sprinkled

starych

Pointers can be used

wagirr

No . References are actually safe pointers in a sense

huaqi_123

References in C can only use pointers,&is something in C++

yachaoo

The title of the master answered the question

zfy010317

void f(int a){
*(int*)a +=1;

}

c practice

austin_dt

No references in C
References are the stuff of C++

All&in C means address or operator.

yachaoo

References are accessed through pointers, but the compiler does&and * operations for you. In C, you cannot achieve your purpose without *a as a parameter.