A java written question, thought it was very simple, but I didn't write it right for a long time! Please prawn give a c

daike1017

Give an arabic number
For example: 123456789
Output: One hundred million, three hundred, five thousand, ten thousand, and ten thousand

I thought this function was very simple, but found that if there are multiple zeros in the middle of the number, there will be problems

Post my code, it's bad
    public static String daxie (int sum)
    {
        String [] n = new String [10];
        n [0] = "zero";
        n [1] = "One";
        n [2] = "贰";
        n [3] = "三";
        n [4] = "肆";
        n [5] = "伍";
        n [6] = "陆";
        n [7] = "柒";
        n [8] = "捌";
        n [9] = "玖";
        String [] d = new String [10];
        d [0] = "";
        d [1] = "";
        d [2] = "pick up";
        d [3] = "百";
        d [4] = "仟";
        d [5] = "万";
        d [6] = "pick up";
        d [7] = "百";
        d [8] = "仟";
        d [9] = "billion";
        // Calculate the number of digits
        int wei = (int) Math.floor
                (
                Math.log10 ((double) sum)
                ) +1;
        System.out.println (wei);
        String str = "";
        int digit = 0;
        for (int i = wei; i> 0; i--)
        {
            digit = sum /
            (int) Math.pow (10.0, (double) (i-1));
            str + = n [digit] .toString () + d [i] .toString ();
            sum = sum%
            (int) Math.pow (10.0, (double) (i-1));
        }

        str = str.replace ("pick up", "pick up");
        str = str.replace ("Zero Pickup", "Zero");
           str = str.replace ("零 百", "Zero");
           str = str.replace ("zero 仟", "zero");
           str = str.replace ("zero million", "million");
          for (int i = 1; i <= 6; i ++)
         str = str.replace ("zero zero", "zero");
         str = str.replace ("Zero million", "Zero");
         str = str.replace ("billion", "billion");
         str = str.replace ("zero zero", "zero");
        if (str.endsWith ("zero"))
        {
            str = str.substring (0, str.length ()-1);
        }
        System.out.println (str);
        return str;
    }

cloudyangyan

String [] d = new String [10];
d [0] = "";
d [1] = "";
d [2] = "pick up";
d [3] = "百";
d [4] = "仟";
d [5] = "万";
d [6] = "pick up";
d [7] = "百";
d [8] = "仟";
d [9] = "billion";
If you define this to the ninth position, then if the number has 10 or more digits, it will be out of bounds.
In addition, in the judgment of thousands, I think it is necessary to add a judgment
if (wei <5) {
str = str.replace ("Zero million", "Zero");
} else {
str = str.replace ("zero million", "million");
}

daike1017

cloudyangyanI changed it according to your method and still have problems

ws286699

[quote] [size = 2] [url = forum.php? mod = redirect&goto = findpost&pid = 9946&ptid = 1673] [color = # 999999]daike1017Posted on 2020-3-22 20:00 [/ color] [/ url] [/ size]
cloudyangyanI changed it according to your method, there are still problems [/ quote]

Is it like this?
[attach] 6 [/ attach]

nanase

class Test
{
    public static void main (String [] args)
    {
        String num = "零 一 贰 三 肆 伍 陆 柒 捌 玖";
        String dw = "Around a hundred trillion yuan";
        String m = "35602001.23";
        String mm [] = null;
        mm = m.split ("\\.");
        String money = mm [0];

        String result = num.charAt (Integer.parseInt ("" + mm [1] .charAt (0))) +
            "Corner" +
            num.charAt (Integer.parseInt ("" + mm [1] .charAt (1))) + "minute";

        for (int i = 0; i <money.length (); i ++)
        {
            String str = "";
            int n = Integer.parseInt (money.substring (money.length ()-i-1,
                money.length ()-i));
            str = str + num.charAt (n);
            if (i == 0)
            {
                str = str + dw.charAt (i);
            }
            else if ((i + 4)% 8 == 0)
            {
                str = str + dw.charAt (4);
            }
            else if (i% 8 == 0)
            {
                str = str + dw.charAt (5);
            }
            else
            {
                str = str + dw.charAt (i% 4);
            }
            result = str + result;
        }
        result = result.replaceAll ("零 万", "万");
        result = result.replaceAll ("zero ([^ 圆] {1})", "zero");
        result = result.replaceAll ("zero +", "zero");
        result = result.replaceAll ("zero circle", "circle");
        result = result.replaceAll ("零 万", "万");
        System.out.println (result);

    }
}

Roughly tested, lz verify to see if there is a problem

meisei

public class Rectangle
{
    public static String daxie (int sum)
    {
        String [] n = new String [10];
        n [0] = "";
        n [1] = "One";
        n [2] = "贰";
        n [3] = "三";
        n [4] = "肆";
        n [5] = "伍";
        n [6] = "陆";
        n [7] = "柒";
        n [8] = "捌";
        n [9] = "玖";
        String [] d = new String [10];
        d [0] = "";
        d [1] = "pick up";
        d [2] = "百";
        d [3] = "仟";
        String [] e = new String [10];
        e [0] = "万";
        e [1] = "billion";

        // Calculate the number of digits
// int wei = (int) Math.floor
// (
// Math.log10 ((double) sum)
//) +1;
        String old = "" + sum;
        int wei = (old) .length ();
System.out.println ("Calculated number of digits ==" + wei);
        
        ArrayList str = new ArrayList ();
        int digit = 0;
        int digit1 = 0;
        for (int i = wei-1; i> = 0; i-) {
            if (! "0" .equals ("" + old.charAt (i))) {
                str.add (0, d [digit]);
                str.add (0, n [Integer.parseInt ("" + old.charAt (i))]);
                            }
                digit ++;
                if (digit == 4) {
                    digit = 0;
                    str.add (0, e [digit1]);
                    digit1 ++;
                }
        }
        System.out.println (str);
        return str.toString ();
    }

    public static void main (String [] args)
    {
        System.out.println (daxie (100212334));
    }
}


Calculate the number of digits == 9
[One, billion, ten, ten, one, ten, ten, ten, three, three hundred, three, ten, four,]
[One, billion, ten, ten, one, ten, ten, ten, three, three hundred, three, ten, four,]

See for yourself

daike1017

meisei
You enter
10000004
Try

Calculate the number of digits == 8
[Billion, one, one, ten thousand, wanton,]
its not right

qaqa5311

I tested it. I ca n’t find anything wrong. Please give pointers. Which numbers will be problematic ???

qaqa5311

lz the one,

daike1017

I am the landlord
My program
Input: 10000004

Output: one

It should be: