I now have a full-screen display. When I want to move the mouse to the top area of the screen when the screen is full, the menu is displayed. When I move the mouse away, the menu disappears again. How do I implement this operation?
If you use C ++ specifically, you don't know, but if you use VC, it should not be too difficult.
This "menu" is made into a special control. For example, after the mouse is moved over him, his coordinate Y value is added to his height (coordinate X is small, but cannot be 0 so that the mouse can be moved to it). If you remove it, you will reduce his height, so that it will become a "menu" when you move up and disappear.
Of course, this method is stupid. Don't laugh at me
I am now in full screen display mode and the menu has disappeared. The problem now is to display it, but not return to normal display mode. The state is still in full screen display mode, but the mouse is moved to the top part of the screen. Area, the menu for that main frame appears on top
In fact, my requirement is the same as the full-screen display of word. When the mouse is moved to the top of the full-screen display interface, the menu appears, and the menu disappears.
Tracking the mouse position (OnMouseMove), if the Y coordinate is 0, the state T is set to 1, otherwise it is set to 0. Handle the mouse hovering message, if the state T is 1, and the menu does not exist, then display the menu; if the state T is 0, and the state exists, delete the menu.
How to display? ? ? It is how to determine the position of the menu display. In the process of processing the full screen display, I do not directly hide the menu, but expand the client area to the entire screen range.
When I was doing full screen, I used the source code in "MFC Classic Q & A". It is a menu with full screen. So at that time I had to hide the menu. The landlord can refer to this source code.
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China
Post time: 2020-1-24 07:20:01
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