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 China

Post time: 2020-1-20 10:00:01
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Prints out something like
1
twenty one
321
4321
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 China

Post time: 2020-1-28 20:36:01
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You can do this:
#include <iostream>
using namespace std;
int main ()
{
int i;
int j;
for (i = 1; i <= 4; i ++)
{
for (j = i; j> 0; j--)
cout << j;
cout << endl;
}
return 0;
}
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 China

Post time: 2020-1-28 22:27:01
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int main ()
{
for (int i = 1; i <5; ++ i)
{
for (int j = i; j> 0; j--)
cout << j;
cout << endl;
}
Ranch

return 0;
}
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 China

Post time: 2020-1-28 23:00:02
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Wow, I did n’t expect a faster one
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 Author| Post time: 2020-1-29 09:09:01
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Didn't say complete, it's my fault. I want to make two codes in C. I don't understand.
sweat!!!
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 China

Post time: 2020-1-29 11:00:01
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Halo changed cout to prinf
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Post time: 2020-2-1 22:18:01
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int main ()
{
  printf ("1");
  printf ("21");
  printf ("321");
  printf ("4321");
  return 0;
}
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 China

Post time: 2020-2-3 16:45:01
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#include <stdio.h>
#include <stdlib.h>

int main ()
{
    int i, j, n;
    printf ("please input a number:");
    scanf ("% d",&n); // Enter 4 here
    
    for (i = 1; i <= n; i ++)
    {
        for (j = i; j> 0; j--)
        printf ("% d", j);
        printf ("\n");
    }

    system ("PAUSE");
    return 0;
}
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Post time: 2020-2-4 23:30:01
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Haha, I did not expect a faster
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 China

Post time: 2020-2-9 17:15:01
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Ha ha, is this speed faster?
int main ()
{
printf ("1\n 21\n321\n4321") ;;
return 0;
}
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