How to take a function as a formal parameter into another function for execution?

royleiy

Like the title, please tell me more in detail. Thank you

1231456

Speak with code

#include <stdio.h>
#include <stdlib.h>

void fun1( int i, double d ){
  printf("fun1: i=%d d=%f\n",i,d);
}


void fun2( int i, double d ){
  printf("fun2: i=%d d=%f\n",i,d);
}

void F(int x, double y, void (*func)( int, double ))
{
        func(x,y);

}

int main()
{
  F(1,2,&fun1);
  F(1,2,&fun2);
  exit(0);

}

霜之哀愁

Just pass a function pointer type to the formal parameters of the function.
The one upstairs is correct. . . .

2511718

With function pointer

holyalien

Function pointer

sevenbox

1231456
correct

hamnhamn3

It is recommended to use typedef to define function pointers