Ask a bit arithmetic problem!

eufhbb

Fill in a blank question and fill in the results:
int x;
(x&1) + (x1)-(x% 2) + (~ (~ 0U << 2)) = ______;
Ask the master what the result is, what is the detailed calculation process?

王志伟

int x = 0; // There is no initialization x, the discussion is meaningless, so the following discussion assumes that x is initialized to 0

(x&1) == 0 according to logical AND
(x | 1) == 1 according to logical OR
(x% 2) == 0 is equivalent to (x&1)
(~ (~ 0U << 2)) == 3 0 is inverted, all bits are 1, and then shifted to the left by two bits, then the next two bits are 0, and then inverted, then the first 1 is all 0, the latter Get two 1s, converted to decimal 3

eufhbb

The x of the title is not assigned, but the stable result can be obtained by debugging with tc. The result is output as 914 as% d, and what does the U in the last registration mean?

cyqi2002

U is unsigned

hogarth

It's so complicated. It's the interview. There will be abnormal questions in the interview.

squallxuk

This question is meaningless, x is not initialized and will be given a random value depending on the compilation environment
The result is (x | 1) +3, your so-called stable result is just given by your environment

elemental_ty

Consensus with LS.