| |

VerySource

 Forgot password?
 Register
Search
View: 651|Reply: 2

Debugging question: What does USER32! 77d18734 () mean in the call stack window?

[Copy link]

2

Threads

3

Posts

4.00

Credits

Newbie

Rank: 1

Credits
4.00

 China

Post time: 2020-1-8 14:20:01
| Show all posts |Read mode
1. When debugging,
What does USER32! 77d18734 () in the call stack window mean?

2, the stack window window shows the function call process of the executing thread,
I want to see the function call process of other threads that have been executed. How do I look at it?

3. How do I know which module (dll or exe) the executing code belongs to in the assembly code displayed in the disassembly window?
Reply

Use magic Report

0

Threads

30

Posts

22.00

Credits

Newbie

Rank: 1

Credits
22.00

 China

Post time: 2020-1-9 11:18:02
| Show all posts
Virtual address of a function in the 1.user32.dll module
2.win32 threads are not executed concurrently, so you can only look at one thread stack at a time
Reply

Use magic Report

0

Threads

24

Posts

19.00

Credits

Newbie

Rank: 1

Credits
19.00

 China

Post time: 2020-1-9 17:09:01
| Show all posts
USER32! 77d18734 () doesn't really mean much to users. The key is to find bugs in your code.
Reply

Use magic Report

You have to log in before you can reply Login | Register

Points Rules

Contact us|Archive|Mobile|CopyRight © 2008-2023|verysource.com ( 京ICP备17048824号-1 )

Quick Reply To Top Return to the list