Delete question !!

两块钱的邦威

void INput :: deleteemployee () {
string name;
list <CEmployee *> :: iterator it = pEmplist.begin ();
list <CEmployee *> :: iterator it_end = pEmplist.end ();
cout << "Please enter the name of the employee you want to delete:"; cin >> name; // output the name of the person to delete
while (it! = it_end) // Sequence search for the person to delete
{if ((** it) .EmpolyeeName () == name)
{pEmplist.erase (it);
// cout << "The employee information you want to delete has been deleted" << endl;
break;}
it ++;
}
if (it == it_end) // Cannot find the user to delete
cout << "sorry, there is no one that you want!" << endl;
}
I'm depressed, it still works. It doesn't work now, it seems to be pEmplist.erase (it);
list <CEmployee *> I have user information here
The masters give pointers!

superandy

Just use list :: remove

两块钱的邦威

How to use it! Brother, I won't. I only know erase other things ... I hope the master can help !!

firegun

if (it == it_end) // Can't find the user to delete
------------------------------------------------
I think there is something wrong with this sentence, if the deleted one is the last one

两块钱的邦威

Brother, change to pEmplist.remove (* it); break; still pop up a window at runtime What is the ASSERT value class

两块钱的邦威

When I tried, instead of deleting the last one, an error popped up in a window ...

firegun

c.remove (val) removes all elements with value val in c (list)

julines

void INput :: deleteemployee () {
string name;
cout << "Please enter the name of the employee you want to delete:"; cin >> name;

for (list <CEmployee *> :: iterator it = pEmplist.begin (); it! = pEmplist.end (); it ++)
if ((** it) .EmpolyeeName () == name)
break;

if (it == it_end)
cout << "sorry, there is no one that you want!" << endl;
else
pEmplist.erase (it);

}