Give me advice

terrorlin

return str16;

linhanerror

Random r=new Random(0);
int iTemp=r.Next(64);
string strRen="01";//Initial
strRen=strRen+Convert.ToString(iTemp, 2).PadLeft(6,'0');
for(int i=0;i<7;i++)
{
strRen+=Convert.ToString(r.Next(256),2).PadLeft(8,'0');
}//I don't know if it means

peng16889

Random generation is all you need to generate randomly?

star811

Random random out a number

kalian2000

Since the 62 bits are random, then it is directly looped 62 times to generate a random number of 0 or 1.

Random rd = new Random();
            string strRen = "01";
            for (int i = 0; i <62; i++)
            {
                strRen += rd.Next(2).ToString();
            }

I wonder if my understanding is wrong?

acadia

for(int i=0; i<64,i++)
{//The following is the pseudo code
   d = A random number every time: odd number is 1, even number is 0;
   SetBit(i, d);
}

The first part is fixed, it is not a problem:
//The first part is 00
SetBit(0,0);
SetBit(1,0);
//The first part is 01
SetBit(0,0);
SetBit(1,1);
//The first part is 10
SetBit(0,1);
SetBit(1,0);
//The first part is 11
SetBit(0,1);
SetBit(1,1);

Whichever you want, just add it after the loop ends.
Within the SetBit function, it is sufficient to use bit operations to set specific bits, which should not be difficult to achieve.

acadia

To add, the landlord finds an Int64 or UInt64 variable to perform SetBit function operation on it.

zyzyzy22

long xx=new Random().Next()+new Random(tmp).Next(); //Generate a 64-bit number

xx=xx&0011111...1B; //Head 2 is 00
xx=xx | 1100000...0B; //Modify the first 2 digits to a fixed number
//Modify the first 2 digits as fixed numbers, where the fixed number is 11

sephiroth999

Isn't it 64 bit?
Then directly generate a random long int (note that on a 32-bit machine, it may be 32-bit, the same as int).
Then use bitset to set the first two bits to 00, 01, 10, or 11,
Then take 3 digits, 14 digits, 20 digits, 25 digits,
Isn't it all random?