rms storage how to store int array data

snowilove

ByteArrayOutputStream baops = new ByteArrayOutputStream();
DataOutputStream outputStream = new DataOutputStream(baops);
outputStream.writeInt();

feixinwei

public static byte[] int2Byte(int n) {
return new byte[] {(byte) ((n >> 24)&0xff),
(byte) ((n >> 16)&0xff), (byte) ((n >> 8)&0xff),
(byte) (n&0xff) };

}

wahaha399

There are 2 ways.
1. Encode int first
  ByteArrrayOutputStream baos = new ByteArrayOutputStream();
  DataOutputStream dos = new DataOutputStream();
  dos.writeInt(i);//i is your integer data

  byte[] result = null;
  result = baos.toByteArray();

  Decode when used:
  ByteArrayInputStream bais = new ByteArrayInputStream();
  DataInputStream dis = new DataInputStream();
  
  int i = dis.readInt();

2.
  byte[] b = new byte[4]; (Int is 32 bits)
  b[0] = (byte)(0xff&(i >> 24));
  b[1] = (byte)(0xff&(i >> 16));
  b[2] = (byte)(0xff&(i >> 8));
  b[3] = (byte)(0xff&(i >> 0));

sindbad

Seeing so many of you, String is the easiest!
public void save(int n)
{
String s=new String(""+n); //Integer becomes a string.
rs.write(s.getBytes(),0,s.length); //Assuming rs is your Record object
}
public int get(int position)
{
byte[] temp=rs.getRecord(position);
return Integer.parseInt(new String(temp));
}

童话中的宝宝

It is best not to use string. If you save both int and short, string and byte[], wouldn't it be troublesome...

残花落雪

byte[] result = null;
  result = baos.toByteArray();
what's the point?

残花落雪

int i = dis.readInt();
dos.writeInt(i);
Are these two I the same?

wahaha399

int i = dis.readInt();
dos.writeInt(i);
Are these two I the same?

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the same